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REVERSE LENGTH DIVISBLE
Reverse Length Divisible Given a number N, check if it is
reverse length divisible. A number is said to be reverse
length divisible if the first i digits of the number is
divisible by (l-i+1) where l is the number of digits in N
and 0 < i <= l.
For example, 652281 is reverse length divisible because:
6 is divisible by 6
65 is divisible by 5
652 is divisible by 4
6522 is divisible by 3
65228 is divisible by 2
652281 is divisible by 1.
43268 is not reverse length divisible. Print Yes if the
number is reverse length divisible and no otherwise.
Boundary Conditions:
0 ≤ n ≤ 100000
Input Format:
The first line contains the number N.
Output Format:
Print "Yes" if the number is reverse length divisible
otherwise print "No" (without quotes).
Reverse Length Divisible Given a number N, check if it is
reverse length divisible. A number is said to be reverse
length divisible if the first i digits of the number is
divisible by (l-i+1) where l is the number of digits in N
and 0 < i <= l.
For example, 652281 is reverse length divisible because:
6 is divisible by 6
65 is divisible by 5
652 is divisible by 4
6522 is divisible by 3
65228 is divisible by 2
652281 is divisible by 1.
43268 is not reverse length divisible. Print Yes if the
number is reverse length divisible and no otherwise.
Boundary Conditions:
0 ≤ n ≤ 100000
Input Format:
The first line contains the number N.
Output Format:
Print "Yes" if the number is reverse length divisible
otherwise print "No" (without quotes).
7 regular answers available
Python Code
n=input()
a=[]
c=0
l=len(n)
val=0
for i in range(l):
a.append(n[0:i+1])
for j in range(l):
val=str(val)
val=a[j]
if(int(val)%(l-j)==0):
c+=1
if(c==l):
print("Yes")
else:
print("No")
what is wrong with my code can anybody help plzz?
#include <iostream>
using namespace std;
int main() {
int n;
cin>>n;
int val=0,count=0;
while(n!=0)
{
count++;
val=n%count;
cout<<count<<" "<<val<<" "<<n<<'\n';
if(val!=0)
{
cout<<"NO";
break;
}
n=n/10;
}
if(n==0)
cout<<"YES";
// your code goes here
return 0;
}
HI VISHAL MISHRA, i tried executing your code ,
it show output for the input
input:
652281
output:
1 0 652281
2 0 65228
3 0 6522
4 0 652
5 0 65
6 0 6
YES
Actually you see the first column of output , its in wrong
order,
it should be like
6 0 652281
5 0 65228
4 0 6522
3 0 652
2 0 65
1 0 6
YES
and the third column should be divisible by first column.
if all are divisible , then you can print "yes" or its "NO
showing WA
#include <iostream>
#include<vector>
#include <list>
#include <stack>
#include<queue>
#include <map>
#include <set>
#include<algorithm>
#include<iomanip>
#include <math.h>
#include <stdio.h>
#include<string.h>
#include <stdlib.h>
using namespace std;
#define ff first
#define ss second
#define int long long
#define pb push_back
#define mp make_pair
#define pii pair<int,int>
#define vi vector<int>
#define mii map<int,int>
#define mod 1000000007
#define int long long
#define w(t) int t; cin>>t; while(t--)
int countDigit(int n)
{
int count = 0;
while (n != 0) {
n = n / 10;
++count;
}
return count;
}
int32_t main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int n, Number = 0, remainder,l;
int flag,k;
cin >> n;
while (n != 0) {
remainder = n % 10;
Number = Number * 10 + (remainder - 2);
n /= 10;
}
l = countDigit(Number);
flag = 1;
for (int i = 0; i <= l; i++) {
k = Number % 10;
if (k % (l - i + 1) != 0) {
flag = 0;
cout << "No";
break;
}
Number = Number / 10;
}
if (flag == 1) {
cout << "Yes";
}
return 0;
}
Hi Vishal Mishra , i have updated your code , maybe this will work ,
check it out
#include <iostream>
using namespace std;
int main() {
int n,c=0;
cin>>n;
int val=0,count=0;
while(n!=0)
{
count++;
if(n%count==0)
{
c++;
}
//cout<<count<<" "<<val<<" "<<n<<'\n';
n=n/10;
}
if(count==c)
cout<<"Yes"<<endl;
else
cout<<"No"<<endl;
// your code goes here
return 0;
}
what is wrong with this code?
int main() {
int n;
cin>>n;
int l=0;
while(n){
l++;
n=n/10;
}
//cout<<l<<endl;
int k=l;
for(int i=1;i<=l;i++){
int temp=n/pow(10,k-1);
if(temp%(l-i+1)!=0){
cout<<"No"<<endl;
break;
}
k--;
}
cout<<"Yes"<<endl;
return 0;
}
hi
but the question says that it should be divisible by (l - i + 1)
can you plzz compare MY code with ABHISHEK RAO'S code and tell me what is the difference because
his code got AC mark .