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Chef and digits of a number
Chef has a number D containing only digits 0's and 1's. He wants to make the number to have all the digits same. For that, he
will change exactly one digit, i.e. from 0 to 1 or from 1 to 0. If it is possible to make all digits equal (either all 0's or
all 1's) by flipping exactly 1 digit then output "Yes", else print "No" (quotes for clarity) .
Input
The first line will contain an integer T representing the number of test cases.
Each test case contain a number made of only digits 1's and 0's on newline
Output
Print T lines with a "Yes" or a "No", depending on whether its possible to make it all 0s or 1s or not.
Chef has a number D containing only digits 0's and 1's. He wants to make the number to have all the digits same. For that, he
will change exactly one digit, i.e. from 0 to 1 or from 1 to 0. If it is possible to make all digits equal (either all 0's or
all 1's) by flipping exactly 1 digit then output "Yes", else print "No" (quotes for clarity) .
Input
The first line will contain an integer T representing the number of test cases.
Each test case contain a number made of only digits 1's and 0's on newline
Output
Print T lines with a "Yes" or a "No", depending on whether its possible to make it all 0s or 1s or not.
2 regular answers available
Python Code:-
for t in range(int(input())):
n=input()
n1=n.count('1')
n0=n.count('0')
if(n1==1 or n0==1):
print("Yes")
else:
print("No")
Python code
# author : SJ
zero=0
one =0
for t in range(int(input())):
s = (input())
for i in s:
if i=='0':
zero+=1
else:
one+=1
if one>zero and one-zero==1:
print("Yes")
elif zero>one and zero-one==1:
print("Yes")
else:
print("No")